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0=5x^2-4x-672
We move all terms to the left:
0-(5x^2-4x-672)=0
We add all the numbers together, and all the variables
-(5x^2-4x-672)=0
We get rid of parentheses
-5x^2+4x+672=0
a = -5; b = 4; c = +672;
Δ = b2-4ac
Δ = 42-4·(-5)·672
Δ = 13456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{13456}=116$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-116}{2*-5}=\frac{-120}{-10} =+12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+116}{2*-5}=\frac{112}{-10} =-11+1/5 $
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